HW problem 5H.3 in 7th ed

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LaurenJuul_1B
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Joined: Fri Sep 28, 2018 12:17 am

HW problem 5H.3 in 7th ed

Postby LaurenJuul_1B » Mon Jan 21, 2019 1:54 pm

Use the information in table 5G.2 to determine the value of K at 300 K for the reaction 2BrCl(g) + H2(g) --> <-- Br2(g) + 2HCl(g)

How do you use the table to determine this? I'm a bit stuck because I'm not sure which reaction to use in the table since none match the one given. Would I use the first reaction given in the table with the 4th somehow since combined those produce the reaction given in the question?

aisteles1G
Posts: 117
Joined: Fri Sep 28, 2018 12:15 am

Re: HW problem 5H.3 in 7th ed

Postby aisteles1G » Mon Jan 21, 2019 2:00 pm

You use two reactions and multiply their K values to get the one for this new one, there is an example of such a problem in the 5H chapter of the book. You would use H2+cl2->2HCl and then 2BrCl-->Br2+Cl2 and multiply their K values

Margaret Akey
Posts: 80
Joined: Fri Sep 28, 2018 12:18 am

Re: HW problem 5H.3 in 7th ed

Postby Margaret Akey » Mon Jan 21, 2019 2:02 pm

Find the two reactions in the table, and when you add the two reactions together, the Cl- end up canceling. Then you are left with the correct chemical equation, and you take the two equilibrium constants and multiply them to get the equilibrium constant for the combined reaction.


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