6th edition 12.69 Ka

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Arianna Ko 2E
Posts: 33
Joined: Fri Sep 28, 2018 12:20 am

6th edition 12.69 Ka

Postby Arianna Ko 2E » Mon Jan 21, 2019 10:32 pm

Does anyone know where the Ka value of 1.4x10^-5 came from for Al(H2O)5OH2+?

Karyn Nguyen 1K
Posts: 72
Joined: Fri Apr 06, 2018 11:04 am

Re: 6th edition 12.69 Ka

Postby Karyn Nguyen 1K » Mon Jan 21, 2019 10:37 pm

I have the same question too! I looked at Tables 12.1 and 12.2 but I didn't see the K value for it.

Karyn Nguyen 1K
Posts: 72
Joined: Fri Apr 06, 2018 11:04 am

Re: 6th edition 12.69 Ka

Postby Karyn Nguyen 1K » Mon Jan 21, 2019 10:40 pm

Also, are we expected to be know how to write the chemical reaction?

Elisa Bass 4L
Posts: 61
Joined: Fri Sep 28, 2018 12:23 am

Re: 6th edition 12.69 Ka

Postby Elisa Bass 4L » Mon Jan 21, 2019 10:44 pm

The value of Ka will probably be given to you on the test. Also you will probably need to know how to write a reaction similar to this. Basically, whenever a salt with a highly charged small cation is dissolved, the cation surrounds itself with the maximum number of water molecules, 6, which is what has happened here. Then that complex is able to act as an acid.


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