Hmwrk 11.57 6th edition

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Lina Petrossian 1D
Posts: 77
Joined: Fri Oct 05, 2018 12:16 am

Hmwrk 11.57 6th edition

Postby Lina Petrossian 1D » Tue Jan 22, 2019 12:56 pm

11.57 A reaction mixture consisting of 2.00 mol CO and 3.00 mol H2 is placed in a 10.0-L reaction vessel and heated to 1200. K. At equilibrium, 0.478 mol CH4 was present in the system. Determine the value of Kc for the reaction
CO(g) + 3 H2(g) <--> CH4(g) + H2O(g) at 1200. K.

Is anyone else getting 3.909?

Manya Bali 4E
Posts: 66
Joined: Fri Sep 28, 2018 12:23 am

Re: Hmwrk 11.57 6th edition

Postby Manya Bali 4E » Tue Jan 22, 2019 1:51 pm

What numbers are you inputting? Don't forget to add the appropriate power for concentrations of substances that have coefficients in the chemical reaction. For me, I have Kc = [CH4][H2O]/[CO][H2]^3 = (.0478)(.0478)/(.152)(.157)^3 = 3.88.

Let me know if you have any questions about where these numbers come from since we have to make an ICE table.

Emily Kennedy 4L
Posts: 57
Joined: Fri Sep 28, 2018 12:25 am
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Re: Hmwrk 11.57 6th edition

Postby Emily Kennedy 4L » Thu Jan 24, 2019 4:06 pm

how do you find the number of moles of H2O ?

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