7th Edition 6E.3

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Ethan Breaux 2F
Posts: 63
Joined: Sat Sep 29, 2018 12:16 am

7th Edition 6E.3

Postby Ethan Breaux 2F » Tue Jan 22, 2019 2:51 pm

Calculate the pH of 0.15 M H2SO4 (aq) at 25 Celsius (Ka2 = 1.2 x 10^-2)

Could someone explain the concept of Ka2 and why we ignore the second ionization?

Emily Ng_4C
Posts: 65
Joined: Fri Sep 28, 2018 12:17 am

Re: 7th Edition 6E.3

Postby Emily Ng_4C » Tue Jan 22, 2019 3:07 pm

Ka2 represents the second reaction that polyprotic compounds often go through. In this case, H2SO4's second reaction (HSO4- +H20 --> SO42- +H3O+) produces an insignificant amount of H3O+ that we ignore the second ionization.


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