7th edition 6D.5

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AhYeon_Kwon_2H
Posts: 48
Joined: Fri Sep 28, 2018 12:27 am

7th edition 6D.5

Postby AhYeon_Kwon_2H » Thu Jan 24, 2019 10:41 am

Calculate the pH, pOH, and percentage protonation of solute in each of the following aqueous solutions: (a) 0.057M NH3(aq); etc.

How do we find the OH- concentration without the Kb given?

Fionna Shue 4L
Posts: 59
Joined: Fri Sep 28, 2018 12:18 am

Re: 7th edition 6D.5

Postby Fionna Shue 4L » Thu Jan 24, 2019 10:54 am

Given Ka, you can find the H+ concentration and the pH value. pOH = 14- pH and the concentration of OH- is 10^(-pOH).

Another way of finding the concentration of OH- is knowing that [OH-]*[H+]=10^-14. Once you have the concentration of H+, [OH-]=(10^-14)/[H+]

Margaret Akey
Posts: 80
Joined: Fri Sep 28, 2018 12:18 am

Re: 7th edition 6D.5

Postby Margaret Akey » Thu Jan 24, 2019 3:44 pm

do we have to look up the ka values ourselves in this case?

MAC 4G
Posts: 121
Joined: Wed Sep 18, 2019 12:16 am

Re: 7th edition 6D.5

Postby MAC 4G » Mon Jan 20, 2020 5:18 pm

For this homework question, early in the chapter there was a table that provides all of the Kb values. That's what you would use to determine x in your ICE box, which you could then use to figure out pOH and then pH.


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