## 6th Edition Problem 41

Kevin Tang 4L
Posts: 83
Joined: Fri Sep 28, 2018 12:28 am

### 6th Edition Problem 41

I am stuck on this problem. I did 17.4mg into .0174g and that into 3.95*10^-4 mols/.25L = 1.58*10^-3 M which is the value i have for x in the ice table. But then when i plug it into the equilibrium equation I get 3.944312*10^-9. What am I doing wrong?

Ethan Breaux 2F
Posts: 63
Joined: Sat Sep 29, 2018 12:16 am

### Re: 6th Edition Problem 41

I don't have the 6th edition but I don't see how you could have calculated it so that the initial concentration of a reactant = the value of x... reevaluate how you got the x value. (most problems made you do like x^2/some number)

Kevin Tang 4L
Posts: 83
Joined: Fri Sep 28, 2018 12:28 am

### Re: 6th Edition Problem 41

I realized that when I made my ICE table, I didn't do 2x for the right side which threw off the numbers for the rest of the numbers. After adjusting I got the correct answer.

Kevin Tang 4L
Posts: 83
Joined: Fri Sep 28, 2018 12:28 am

### Re: 6th Edition Problem 41

I realized that when I made my ICE table, I didn't do 2x for the right side which threw off the numbers for the rest of the numbers. After adjusting I got the correct answer.