6th Edition Problem 41

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Kevin Tang 4L
Posts: 83
Joined: Fri Sep 28, 2018 12:28 am

6th Edition Problem 41

Postby Kevin Tang 4L » Fri Jan 25, 2019 12:17 pm

I am stuck on this problem. I did 17.4mg into .0174g and that into 3.95*10^-4 mols/.25L = 1.58*10^-3 M which is the value i have for x in the ice table. But then when i plug it into the equilibrium equation I get 3.944312*10^-9. What am I doing wrong?

Ethan Breaux 2F
Posts: 63
Joined: Sat Sep 29, 2018 12:16 am

Re: 6th Edition Problem 41

Postby Ethan Breaux 2F » Fri Jan 25, 2019 3:19 pm

I don't have the 6th edition but I don't see how you could have calculated it so that the initial concentration of a reactant = the value of x... reevaluate how you got the x value. (most problems made you do like x^2/some number)

Kevin Tang 4L
Posts: 83
Joined: Fri Sep 28, 2018 12:28 am

Re: 6th Edition Problem 41

Postby Kevin Tang 4L » Sun Jan 27, 2019 5:34 pm

I realized that when I made my ICE table, I didn't do 2x for the right side which threw off the numbers for the rest of the numbers. After adjusting I got the correct answer.

Kevin Tang 4L
Posts: 83
Joined: Fri Sep 28, 2018 12:28 am

Re: 6th Edition Problem 41

Postby Kevin Tang 4L » Sun Jan 27, 2019 5:36 pm

I realized that when I made my ICE table, I didn't do 2x for the right side which threw off the numbers for the rest of the numbers. After adjusting I got the correct answer.


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