11.89 6th edition

Moderators: Chem_Mod, Chem_Admin

Griffin Carter 2I
Posts: 16
Joined: Wed Nov 14, 2018 12:23 am

11.89 6th edition

Postby Griffin Carter 2I » Sun Feb 10, 2019 12:13 pm

In part b why are all of the partial pressure values for Kp divided by 100? Is this an approximation of the standard pressure in kPa?

Xuan Kuang 2L
Posts: 31
Joined: Wed Nov 14, 2018 12:23 am

Re: 11.89 6th edition

Postby Xuan Kuang 2L » Sun Feb 10, 2019 4:03 pm

Yes, I believe that is the case because they're converting it to atm I think.


Return to “Equilibrium Constants & Calculating Concentrations”

Who is online

Users browsing this forum: No registered users and 1 guest