Problem #4 on Test #1

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Brevin Hensley 1C
Posts: 24
Joined: Fri Sep 28, 2018 12:25 am

Problem #4 on Test #1

Postby Brevin Hensley 1C » Wed Feb 13, 2019 9:42 am

Question: At -100C, Kp =0.13 for the reaction CO2(s) <> CO2(g). What is the equilibrium partial pressure of CO2(g) at -100C?

I would appreciate if someone could explain to me the answer, thank you.

Andrea Zheng 1H
Posts: 61
Joined: Fri Sep 28, 2018 12:26 am

Re: Problem #4 on Test #1

Postby Andrea Zheng 1H » Wed Feb 13, 2019 10:18 am

Kp for any reaction is = [products]/[reactants] but you wouldn't include solids or liquids in this eq constant. Because the reactant is a solid, the only thing that affects Kp is the products. Therefore, Kp = [products] = 0.13. This means the [CO2(g)] = 0.13 atm.

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