Midterm, Question 2.B

Moderators: Chem_Mod, Chem_Admin

Ahmed Mahmood 4D
Posts: 72
Joined: Fri Sep 28, 2018 12:28 am

Midterm, Question 2.B

Postby Ahmed Mahmood 4D » Sat Mar 16, 2019 2:28 pm

Since the researcher’s publication was the reverse reaction of the original reaction, wouldn’t her equillibrium constant just be the inverse of the forward reaction’s equillibrium constant? If not, what is it supposed to be, and why did I get points taken off for my answer?

Adrienne_4F
Posts: 64
Joined: Fri Sep 28, 2018 12:27 am

Re: Midterm, Question 2.B

Postby Adrienne_4F » Sat Mar 16, 2019 3:07 pm

Yes it is inverse. It would be 1 over K of the forward reaction.

aisteles1G
Posts: 117
Joined: Fri Sep 28, 2018 12:15 am

Re: Midterm, Question 2.B

Postby aisteles1G » Sat Mar 16, 2019 3:08 pm

Youre right, the reverse is 1/K and the answer was 1/3.38*10^-4 = 2.96*10^3, maybe your k value from part A was wrong?

Mark 1D
Posts: 63
Joined: Fri Sep 28, 2018 12:18 am

Re: Midterm, Question 2.B

Postby Mark 1D » Sat Mar 16, 2019 6:57 pm

1/K , which is the inverse I believe


Return to “Equilibrium Constants & Calculating Concentrations”

Who is online

Users browsing this forum: No registered users and 1 guest