Chemical Equilibrium Part 2 #19

Amy Luu 2G
Posts: 105
Joined: Wed Sep 18, 2019 12:19 am

Chemical Equilibrium Part 2 #19

Edit: Sorry i wrote the wrong problem. Here is number 19
Calculate the reaction quotient, Qc, from . the following equilibrium data collected in a 3.00 L sealed reaction vessel for the reaction:
2AsH3(g) $\rightleftharpoons$ 2As(s) + 3H2(g)
AsH3= 5.55x10^-4
As= 3.31x10^-3
Hs= 1.23x10^-3

I calculated the moles into molarity by dividing the moles by 3 L and used the equation Qc=$\frac{[As]^2[H2]^3}{[AsH3]^2}$
I got 2x10^-9. What did i do wrong?
Last edited by Amy Luu 2G on Wed Jan 08, 2020 4:53 pm, edited 1 time in total.

Alexis Webb 2B
Posts: 124
Joined: Thu Jul 11, 2019 12:15 am

Re: Chemical Equilibrium Part 2 #19

I am confused because your equation doesn’t match the question. Can you clarify please?

Ryan Chang 1C
Posts: 105
Joined: Sat Aug 24, 2019 12:17 am

Re: Chemical Equilibrium Part 2 #19

You forgot that solids are not factored into the expression, so As should be removed.

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