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5H.3

Posted: Wed Jan 08, 2020 11:44 pm
by Chris Tai 1B
Use the information in Table 5G.2 to determine the value of K at 300 K for the reaction 2 BrCl(g) + 1 H2(g) <-> Br2(g) + 2 HCl(g).

Is there a way to determine the value of K given this table? If so, how?

Re: 5H.3

Posted: Thu Jan 09, 2020 9:06 am
by Christineg1G
You would use the values of K in the table to determine the value of K for the reaction. So you would use K=377 for the expression 2BrCl<->Br2+Cl2 and K=4.0x10^31 for the expression H2+Cl2<->2HCl. You would then multiply the values of K1 and K2 to get your answer.

Re: 5H.3

Posted: Thu Jan 09, 2020 9:45 am
by Caitlyn Tran 2E
If this were a problem on a test, the K values would have to be given to you. The only time you would ever have to calculate K is if you could find the concentrations of all reactants and products or the partial pressures of all reactants and products to plug into the K expression. This is not the case here, which is why the textbook allows you to reference the table. Hope this helps!

Re: 5H.3

Posted: Thu Jan 09, 2020 11:33 am
by 805329408
Does anyone know what the very last column is used for?

Re: 5H.3

Posted: Thu Jan 09, 2020 11:37 am
by 505316964
When you manipulate an equation you also manipulate the K value, which is why you multiply the K values of the two equations to get your composite equation's K value.

For example if you multiply an equation by 2 you square the K value.