## Calculating K

EvanWang
Posts: 81
Joined: Sat Sep 07, 2019 12:16 am

### Calculating K

In a reaction where the only substance that can be inputed into K is on the reactant side (the rest of the reactants and products are either solids or pure liquids), is K calculated as just the concentration of that substance? Or is it the inverse of the concentration?

Baoying Li 1B
Posts: 91
Joined: Sat Aug 17, 2019 12:18 am

### Re: Calculating K

I think it's one over the concentration of the substance as a reactant(neither a solid or pure liquid). This shows the equilibrium constant of the forward reaction whereas the reverse reaction will only be the concentration of the substance.

DHavo_1E
Posts: 90
Joined: Sat Aug 17, 2019 12:17 am

### Re: Calculating K

I agree with the statement above that K would be 1/concentration of the gas or liquid, and would like to add that this is because the activity of pure substances and liquids is 1, which accounts for the right side of the equation of solids and liquids. K = [(activities of products)^n/(activities of reactants)^n).

Tyler Angtuaco 1G
Posts: 106
Joined: Wed Sep 11, 2019 12:16 am

### Re: Calculating K

Kc is always the ratio of the equilibrium concentrations of the products to the reactants, so it would just be 1/(concentration of that reactant).

805291863
Posts: 80
Joined: Sat Sep 14, 2019 12:16 am

### Re: Calculating K

It would be the inverse of the concentration because the value for the products would be 1

William Francis 2E
Posts: 81
Joined: Wed Sep 18, 2019 12:20 am

### Re: Calculating K

It would be the inverse of the one reactant concentration since Kc is always calculated with product concentrations over reactant concentrations. If no reactants' or products' can be input then you just input 1.
Last edited by William Francis 2E on Fri Jan 10, 2020 11:14 am, edited 1 time in total.

ThomasNguyen_Dis1H
Posts: 81
Joined: Fri Aug 30, 2019 12:17 am

### Re: Calculating K

It would be the inverse of the concentration since K is products over reactants