5G.1.C explanation (SSM)

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205405339
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Joined: Thu Jul 11, 2019 12:16 am

5G.1.C explanation (SSM)

Postby 205405339 » Thu Jan 09, 2020 10:04 pm

in the student solutions manual, it says that question C is false because the amount of reactants/products doesn't affect the equilibrium constant if the temperature is constant but the question is asking if the equilibrium constant will increase if the reactant starts at a higher pressure so shouldn't the explanation be that since the partial pressure is the denominator, the equilibrium constant will decrease rather than increase since an increase in the denominator will lead to a decrease in K since the partial pressure of the reactant and K are inversely proportional? Essentially, I am confused why the explanation mentions the quantity of reactant/products not having an effect on K even though the question is focused on the pressure of the reactant.

WesleyWu_1C
Posts: 117
Joined: Thu Jul 25, 2019 12:16 am

Re: 5G.1.C explanation (SSM)

Postby WesleyWu_1C » Fri Jan 10, 2020 1:20 am

I think the explanation is trying to say that even though you might start with an initial higher pressure of reactant, by the time the equation reaches equilibrium, the equilibrium constant K will still be the same. The only thing that changes the equilibrium constant is changing the temperature because K is just a ratio.

Norman Dis4C
Posts: 101
Joined: Sat Sep 28, 2019 12:16 am

Re: 5G.1.C explanation (SSM)

Postby Norman Dis4C » Sun Jan 12, 2020 12:02 pm

The equilibrium constants do not change as long as the temperature stays the same.


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