5I.5

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smurphy1D
Posts: 51
Joined: Mon Nov 18, 2019 12:18 am

5I.5

Postby smurphy1D » Fri Jan 10, 2020 9:21 am

In this equation I am given the value of K and 2 partial pressure values. I need to solve to find the P for the last one. I am dividing and multiplying the other values around to solve for x but I keep getting the wrong answer. Am I forgetting a step?
Ppcl5= Ppcl3 + Pcl2
1.8 bar =(x) + 5.43 bar K=25 25=5.43(x)/1.8. 25 x 1.8/5.43=x

Renee Grange 1I
Posts: 56
Joined: Fri Aug 30, 2019 12:16 am
Been upvoted: 1 time

Re: 5I.5

Postby Renee Grange 1I » Fri Jan 10, 2020 9:30 am

I think the reason you are getting the wrong answer is because you are using 1.8 bar instead of 1.18 bar, but your steps are correct.

Ivan Tadeja 1G
Posts: 81
Joined: Fri Sep 28, 2018 12:28 am

Re: 5I.5

Postby Ivan Tadeja 1G » Fri Jan 10, 2020 10:03 am

You did everything right, change 1.8 to 1.18 and you will get the correct outputs.

Pegah Nasseri 1K
Posts: 100
Joined: Wed Feb 27, 2019 12:15 am

Re: 5I.5

Postby Pegah Nasseri 1K » Fri Jan 10, 2020 3:23 pm

For this problem you know that K=25 so using the chemical equation you know that:

Plug in the values of the partial pressures that have already been given to you:

Then isolate PPCl3 to find its partial pressure:

smurphy1D
Posts: 51
Joined: Mon Nov 18, 2019 12:18 am

Re: 5I.5

Postby smurphy1D » Tue Jan 14, 2020 9:31 pm

Renee Grange 1I wrote:I think the reason you are getting the wrong answer is because you are using 1.8 bar instead of 1.18 bar, but your steps are correct.

Yes, got it thank you!


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