Change in k

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Change in k

Postby 805373590 » Fri Jan 10, 2020 1:26 pm

How is it that a change in concentration does not change the value of k?

Renee Grange 1I
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Re: Change in k

Postby Renee Grange 1I » Fri Jan 10, 2020 1:37 pm

Changing the concentration does not change K because although the concentrations of reactants and products will be different, the overall ration of them in the equilibrium constant will remain the same. Higher concentration of reactant will produce a higher concentration of product.

Haley Dveirin 1E
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Re: Change in k

Postby Haley Dveirin 1E » Fri Jan 10, 2020 1:38 pm

a change in concentration of a reactant causes the concentration of the product to change (and vice versa) so the ration of P/R does not change because both P and R change, meaning K does not change.

Emily Chirila 2E
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Re: Change in k

Postby Emily Chirila 2E » Fri Jan 10, 2020 2:56 pm

The system will adjust in response to the change and thus produce more product, keeping a consistent ratio.

Pegah Nasseri 1K
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Re: Change in k

Postby Pegah Nasseri 1K » Fri Jan 10, 2020 3:32 pm

Lavelle mentioned in lecture that if more reactant is added to a chemical reaction at equilibrium more product will form until the original product to reactant ratio is maintained. The same is true for when more product is added at equilibrium which causes more reactant to form until the product to reactant ratio remains the same. This demonstrates Le Chatelier's Principle, which shows that K does not change because the chemical reaction adjusts to ensure that the product to reactant ratio remains the same whether more product or reactant is added.

Anna Heckler 2C
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Re: Change in k

Postby Anna Heckler 2C » Fri Jan 10, 2020 4:56 pm

Changing the concentrations of R or P does not affect K because K is a constant. It changes Q, and so you can calculate Q to tell you know the reaction will proceed to return to the given ratio of K.

Ellen Amico 2L
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Re: Change in k

Postby Ellen Amico 2L » Fri Jan 10, 2020 5:28 pm

Because of Le Chatelier's Principle. the reaction will adjust in order to keep the ratio of products to reactants the same. For example, if there's a higher concentration of reactants, the reaction will adjust to have a higher concentration of products. The actual concentrations will change, but the ratio will not.

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Re: Change in k

Postby 005333065 » Sat Jan 11, 2020 11:01 am

According to Le Chatelier's Principle, an equilibrium will act to minimize external disturbances. So, if you increase the concentration of (let's say) the product, the equailibriım will start relying more on to the left side to produce more reactants. This will diminish the change done to the system as the ratios of the concentrations, and so the K value, will be the same.

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Re: Change in k

Postby RRahimtoola1I » Sat Jan 11, 2020 1:18 pm

This is true because of LeChatelier's principle that a reaction will try to minimize change to equilibrium. If more reactants are added the reaction shifts towards the products producing more product in the same ration that K was initially.

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Re: Change in k

Postby san_2F » Sat Jan 11, 2020 1:20 pm

K is the equilibrium constant. The keyword there is constant meaning that for a certain reaction, no matter how much the initial concentration, the K value will always be the same for that reaction.

Nuoya Jiang
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Re: Change in k

Postby Nuoya Jiang » Sat Jan 11, 2020 2:50 pm

K is a constant and if anything of the environment changes, such as the temperature, the system adjusts to the changes, resulting in the constant k.

Madelyn Romberg 1H
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Re: Change in k

Postby Madelyn Romberg 1H » Sat Jan 11, 2020 3:12 pm

K tells us the ratio of concentrations between products and reactants that is most favorable given the current conditions. So, with changing concentrations, you will be changing your Q. Then, the reaction will work to bring Q towards K. The total amount of product and reactant will change, but their ratio will not.

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