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Change in k

Posted: Fri Jan 10, 2020 1:26 pm
by 805373590
How is it that a change in concentration does not change the value of k?

Re: Change in k

Posted: Fri Jan 10, 2020 1:37 pm
by Renee Grange 1I
Changing the concentration does not change K because although the concentrations of reactants and products will be different, the overall ration of them in the equilibrium constant will remain the same. Higher concentration of reactant will produce a higher concentration of product.

Re: Change in k

Posted: Fri Jan 10, 2020 1:38 pm
by Haley Dveirin 1E
a change in concentration of a reactant causes the concentration of the product to change (and vice versa) so the ration of P/R does not change because both P and R change, meaning K does not change.

Re: Change in k

Posted: Fri Jan 10, 2020 2:56 pm
by Emily Chirila 2E
The system will adjust in response to the change and thus produce more product, keeping a consistent ratio.

Re: Change in k

Posted: Fri Jan 10, 2020 3:32 pm
by Pegah Nasseri 1K
Lavelle mentioned in lecture that if more reactant is added to a chemical reaction at equilibrium more product will form until the original product to reactant ratio is maintained. The same is true for when more product is added at equilibrium which causes more reactant to form until the product to reactant ratio remains the same. This demonstrates Le Chatelier's Principle, which shows that K does not change because the chemical reaction adjusts to ensure that the product to reactant ratio remains the same whether more product or reactant is added.

Re: Change in k

Posted: Fri Jan 10, 2020 4:56 pm
by Anna Heckler 2C
Changing the concentrations of R or P does not affect K because K is a constant. It changes Q, and so you can calculate Q to tell you know the reaction will proceed to return to the given ratio of K.

Re: Change in k

Posted: Fri Jan 10, 2020 5:28 pm
by Ellen Amico 2L
Because of Le Chatelier's Principle. the reaction will adjust in order to keep the ratio of products to reactants the same. For example, if there's a higher concentration of reactants, the reaction will adjust to have a higher concentration of products. The actual concentrations will change, but the ratio will not.

Re: Change in k

Posted: Sat Jan 11, 2020 11:01 am
by 005333065
According to Le Chatelier's Principle, an equilibrium will act to minimize external disturbances. So, if you increase the concentration of (let's say) the product, the equailibriÄħm will start relying more on to the left side to produce more reactants. This will diminish the change done to the system as the ratios of the concentrations, and so the K value, will be the same.

Re: Change in k

Posted: Sat Jan 11, 2020 1:18 pm
by RRahimtoola1I
This is true because of LeChatelier's principle that a reaction will try to minimize change to equilibrium. If more reactants are added the reaction shifts towards the products producing more product in the same ration that K was initially.

Re: Change in k

Posted: Sat Jan 11, 2020 1:20 pm
by san_2F
K is the equilibrium constant. The keyword there is constant meaning that for a certain reaction, no matter how much the initial concentration, the K value will always be the same for that reaction.

Re: Change in k

Posted: Sat Jan 11, 2020 2:50 pm
by Nuoya Jiang
K is a constant and if anything of the environment changes, such as the temperature, the system adjusts to the changes, resulting in the constant k.

Re: Change in k

Posted: Sat Jan 11, 2020 3:12 pm
by Madelyn Romberg 1H
K tells us the ratio of concentrations between products and reactants that is most favorable given the current conditions. So, with changing concentrations, you will be changing your Q. Then, the reaction will work to bring Q towards K. The total amount of product and reactant will change, but their ratio will not.