Textbook question 5I.15

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Paige Lee 1A
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Joined: Sat Sep 07, 2019 12:16 am

Textbook question 5I.15

Postby Paige Lee 1A » Sat Jan 11, 2020 9:13 am

Could someone please explain how to find the equilibrium concentration of H2S? Why isn't is 0.2mols/L also?

Hui Qiao Wu 1I
Posts: 56
Joined: Fri Aug 30, 2019 12:16 am

Re: Textbook question 5I.15

Postby Hui Qiao Wu 1I » Sat Jan 11, 2020 10:33 am

Use the equilibrium constant K =[P]/[R] to find the [NH3]. Since NH4HS is a solid, we wouldn't include it in the equation as [R]. The [NH3] is .400/2.0 which is 0.2. Then you plug in the numbers: (1.6 x10^-4) = .2([H2S]). Therefore, the [H2S] is 8 x 10^4.


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