Kw calcuation

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Daniel Yu 1E
Posts: 100
Joined: Sat Aug 24, 2019 12:15 am

Kw calcuation

Postby Daniel Yu 1E » Mon Jan 13, 2020 11:27 am

Why is the activity of water equal to 1 when you are calculating the Kw with [H3O+][OH-]/[H2O]^2?

Benjamin Feng 1B
Posts: 102
Joined: Sat Sep 07, 2019 12:19 am

Re: Kw calcuation

Postby Benjamin Feng 1B » Mon Jan 13, 2020 12:13 pm

Water is the solvent for the equation, and there is a huge excess of it compared to the OH- and H+ ions. This means that even if we did include it, the concentration barely changes.

Joseph Saba
Posts: 154
Joined: Thu Jul 11, 2019 12:16 am

Re: Kw calcuation

Postby Joseph Saba » Mon Jan 13, 2020 12:29 pm

I would suggest to just look at it in terms of concentration, activity seems like an advanced topic for gen chem.

Hannah Romeo 1J
Posts: 58
Joined: Thu Jul 11, 2019 12:16 am

Re: Kw calcuation

Postby Hannah Romeo 1J » Mon Jan 13, 2020 1:30 pm

The Kw equation follows the previous logic of setting up K expressions. Pure solids and liquids are not included in the expression as they are in such excess that there equilibrium concentration is negligible. This results in Kw = [H3O+][OH-] as the molar concentration of hydronium and hydroxide are the only concentrations that change significantly in the reaction.

Mariah
Posts: 104
Joined: Fri Aug 02, 2019 12:16 am

Re: Kw calcuation

Postby Mariah » Mon Jan 13, 2020 2:40 pm

Its basically omitted because it only changes slightly.

AniP_2D
Posts: 95
Joined: Sat Aug 17, 2019 12:17 am

Re: Kw calcuation

Postby AniP_2D » Mon Jan 13, 2020 3:26 pm

Since water is a liquid, it is omitted from the equilibrium constant, giving the denominator in this specific equilibrium constant a value of 1.


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