## 6B.9a

Alicia Lin 2F
Posts: 83
Joined: Wed Sep 18, 2019 12:17 am

### 6B.9a

For the first line, when I type in -log(1.50) to try to get the pH, I keep getting -0.176 but the answer is supposed to be positive 0.176. Also, when I multiply the OH- and H3O+ concentrations in the answer key, I don't get 1.0 x 10^-14. Is this an error in the book?

Justin Vayakone 1C
Posts: 110
Joined: Sat Sep 07, 2019 12:19 am

### Re: 6B.9a

Yeah it looks like the answer key is wrong. The pH should be -0.176. With this pH, the pOH would now be 14.176 and $[OH^-]$ = $6.67 \cdot 10^{-15}$