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Posted: Wed Jan 15, 2020 2:33 pm
by Alicia Lin 2F
For the first line, when I type in -log(1.50) to try to get the pH, I keep getting -0.176 but the answer is supposed to be positive 0.176. Also, when I multiply the OH- and H3O+ concentrations in the answer key, I don't get 1.0 x 10^-14. Is this an error in the book?

Re: 6B.9a

Posted: Wed Jan 15, 2020 2:58 pm
by Justin Vayakone 1C
Yeah it looks like the answer key is wrong. The pH should be -0.176. With this pH, the pOH would now be 14.176 and =