## Help on 5.35

Tiffany Chao 2H
Posts: 117
Joined: Fri Aug 09, 2019 12:17 am

### Help on 5.35

I'm not understanding how to find the chemical equation on 5.35. Can someone help me explain?

Thanks

Selena Yu 1H
Posts: 108
Joined: Fri Aug 09, 2019 12:16 am

### Re: Help on 5.35

It says in the problem that compound A decomposes into compounds B and C. So the chemical equation would be A (g) --> B (g) + C (g)

Rohit Ghosh 4F
Posts: 99
Joined: Thu Jul 25, 2019 12:17 am

### Re: Help on 5.35

You can then use the partial pressures given by the graph along with the reaction A (g) --> B (g) + C (g) to calculate the equilibrium constant.

KBELTRAMI_1E
Posts: 108
Joined: Sat Jul 20, 2019 12:17 am

### Re: Help on 5.35

then just simplify and you should have all parts to the question answered

Tiffany Chao 2H
Posts: 117
Joined: Fri Aug 09, 2019 12:17 am

### Re: Help on 5.35

Selena Yu 1H wrote:It says in the problem that compound A decomposes into compounds B and C. So the chemical equation would be A (g) --> B (g) + C (g)

The answer key says the chemical equation is 2A (g) --> B (g) + 2C (g)

Tiffany Chao 2H
Posts: 117
Joined: Fri Aug 09, 2019 12:17 am

### Re: Help on 5.35

Rohit Ghosh 4F wrote:You can then use the partial pressures given by the graph along with the reaction A (g) --> B (g) + C (g) to calculate the equilibrium constant.

The answer key says the chemical equation is 2A (g) --> B (g) + 2C (g)