5.35 part b

Moderators: Chem_Mod, Chem_Admin

Michelle Song 1I
Posts: 75
Joined: Thu Jul 11, 2019 12:17 am

5.35 part b

Postby Michelle Song 1I » Thu Jan 16, 2020 11:46 am

When calculating the equilibrium constant, the solution divides each of the values given on the plot (which are in kPa) by 100. Is this to convert it from kPa to atm? And if so, does that mean gas equilibrium constants can only be calculated using partial pressures in atm?

VPatankar_2L
Posts: 84
Joined: Thu Jul 25, 2019 12:17 am
Been upvoted: 1 time

Re: 5.35 part b

Postby VPatankar_2L » Thu Jan 16, 2020 12:56 pm

Yes I think you should always convert from Pa to atm or bar before you continue with calculations.

Renee Grange 1I
Posts: 37
Joined: Fri Aug 30, 2019 12:16 am
Been upvoted: 1 time

Re: 5.35 part b

Postby Renee Grange 1I » Thu Jan 16, 2020 1:20 pm

The divide by 100 in order to convert pKa to bar. 1 pKa = .01 bar.

Michelle Song 1I
Posts: 75
Joined: Thu Jul 11, 2019 12:17 am

Re: 5.35 part b

Postby Michelle Song 1I » Thu Jan 16, 2020 2:40 pm

VPatankar_3L wrote:Yes I think you should always convert from Pa to atm or bar before you continue with calculations.
Ah okay, thank you! Did Dr. Lavelle mention this in lecture?

Michelle Song 1I
Posts: 75
Joined: Thu Jul 11, 2019 12:17 am

Re: 5.35 part b

Postby Michelle Song 1I » Thu Jan 16, 2020 2:40 pm

Renee Grange 1I wrote:The divide by 100 in order to convert pKa to bar. 1 pKa = .01 bar.
Thank you! Did he mention this in lecture?


Return to “Equilibrium Constants & Calculating Concentrations”

Who is online

Users browsing this forum: No registered users and 1 guest