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Dina Marchenko 2J
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Postby Dina Marchenko 2J » Thu Jan 16, 2020 9:41 pm

6B3 asks you to find the pH of 0.025 M HCl first in a flask of volume 200.0 mL (part a) and then one of 250.0 mL (part b). I found the new molarity within each new volume and then found the pH of that but in the answers for part a, the book just found the pH of 0.025 M. I don't really get why; don't you need to find the new molarity since the volume of the flask is not 1 L?

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Re: 6B3

Postby Chem_Mod » Thu Jan 16, 2020 11:00 pm

For part a, you would have 200.0mL of a .025M solution, so you don't need to calculate a new molarity since the solution is at the desired concentration.

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