5.39

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Sue Bin Park 2I
Posts: 52
Joined: Mon Jun 17, 2019 7:24 am

5.39

Postby Sue Bin Park 2I » Mon Jan 20, 2020 5:32 pm

Can't figure out why I'm getting an impossibly small amount of NO2...using Kc from 5G.2. Could someone outline the solution? thanks.

DarrenKim_1H
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Joined: Fri Sep 20, 2019 12:17 am
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Re: 5.39

Postby DarrenKim_1H » Mon Jan 20, 2020 10:52 pm

I believe if you are calculating x using the information from Table GE.2, the values you would get for x are 1.47x10^-2 or 6.81x10^-3. But you would use 1.47x10^-2 since anything around 10^-3 is too small (I might be wrong about that, but thats my general rule of thumb lol)

Sue Bin Park 2I
Posts: 52
Joined: Mon Jun 17, 2019 7:24 am

Re: 5.39

Postby Sue Bin Park 2I » Wed Jan 22, 2020 8:48 pm

DarrenKim_3G wrote:I believe if you are calculating x using the information from Table GE.2, the values you would get for x are 1.47x10^-2 or 6.81x10^-3. But you would use 1.47x10^-2 since anything around 10^-3 is too small (I might be wrong about that, but thats my general rule of thumb lol)


which value of K are you using from the table? the inverse of 6.1*10^23?
EDIT: i believe the textbook i have has a typo for the Kc of dinitrogen tetroxide to nitrogen dioxide ... the Kc should be 6.1*10^-3 not 23 lol


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