example 5J.2

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nshahwan 1L
Posts: 100
Joined: Fri Aug 30, 2019 12:18 am

example 5J.2

Postby nshahwan 1L » Tue Jan 21, 2020 9:23 pm

In example 5J.2, it justifies picking 0.0144... over 81.7... for the x value because partial pressures must be positive. However, both of these values are positive. How would you know which positive value to pick?

Brooke Yasuda 2J
Posts: 102
Joined: Sat Jul 20, 2019 12:17 am

Re: example 5J.2

Postby Brooke Yasuda 2J » Tue Jan 21, 2020 9:28 pm

When you look at which value is going to be used, you have to look at whether or not when this value is subtracted from a reactant or product, it will be negative or positive. So assume you start off with some value of reactant and no product. As the system moves towards equilibrium, product is formed and reactant is consumed. The amount of reactant consumed cannot be greater than its initial value because negative amounts of reactant are not possible. So this is what it means when it says the partial pressure must be positive.


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