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Fdonovan 3D
Posts: 101
Joined: Sat Aug 17, 2019 12:16 am


Postby Fdonovan 3D » Wed Jan 22, 2020 5:27 pm

In 6B.9, there is a table that gives you either the [H30+] concentration, the [OH-] concentration, the pH, or the pOH. In the first part of the table, it is given that [H3O+] = 1.50 mol/L and you have to calculate the other things in the table. To get the pH, I did -log[H3O+] = -log(1.5) and I got an answer of -0.176. However, in the answer key the right answer is +0.176. Can someone explain to me where I went wrong?

Alicia Lin 2F
Posts: 83
Joined: Wed Sep 18, 2019 12:17 am

Re: 6B.9

Postby Alicia Lin 2F » Wed Jan 22, 2020 7:12 pm

The answer key is wrong. The calculated pH should be negative.

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