Problem 5I.13

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Morgan Carrington 2H
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Joined: Wed Nov 14, 2018 12:22 am

Problem 5I.13

Postby Morgan Carrington 2H » Wed Jan 22, 2020 11:35 pm

The answer to the question states that the equilibrium of Cl2 is essentially unchanged and then solves the problem by doing 2 * (5.5*10-6). Can someone explain where they found the 5.5*10-6 and why it is multiplied by 2?

Jordan Young 2J
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Re: Problem 5I.13

Postby Jordan Young 2J » Wed Jan 22, 2020 11:48 pm

5.5*10^-6 is the value you get for x when you solve for the change in concentration using the equilibrium constant and it's multiplied by 2 because of the stoichiometric ratios in the equation.

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