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Can someone explain the basics to pKa and pKb. I thought it was the product of the two equals pKw and that their product is equal to 14. And when calculating it, you just need to do the -log of the ja or kb. Is there anything else I should know fundamentally when applying this to a problem?
pKa is -logKa and pKb is -logKb. If you are familiar with the equation Kw= Ka x Kb and the equation Kw= 1.0x 10^-14, you can make the equation Ka x Kb= Kw= 1.0x 10^-14. Then, you can fill multiply the equation by -log and convert it to Kb and pKa. When you do this, you get the equation pKb + pKa = 14.
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