Midterm 3D

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705121606
Posts: 68
Joined: Wed Sep 18, 2019 12:17 am

Midterm 3D

Postby 705121606 » Wed Feb 26, 2020 10:02 pm

For this question, it was asking what the net charge for acetic acid is when at ph 6 and pka 4.75. I was confused because I thought acids don't have charges. I wrote that the acid is neutral because when is dissociates wouldn't it become the conjugate base instead?

Amanda Lin 2I
Posts: 101
Joined: Sat Aug 17, 2019 12:15 am

Re: Midterm 3D

Postby Amanda Lin 2I » Wed Feb 26, 2020 10:32 pm

Because the pH is higher than the pKa, CH3COOH will be deprotonated, forming CH3COO-, which has a charge of -1.

Julie_Reyes1B
Posts: 105
Joined: Sat Jul 20, 2019 12:16 am

Re: Midterm 3D

Postby Julie_Reyes1B » Wed Feb 26, 2020 10:34 pm

Because pH>pKa, the acid will mostly deprotonate. Since it deprotonates it will become the conjugate base, ChH3COO-. The conjugate base will have a net charge of -1.

705121606
Posts: 68
Joined: Wed Sep 18, 2019 12:17 am

Re: Midterm 3D

Postby 705121606 » Thu Feb 27, 2020 12:27 am

Julie_Reyes1B wrote:Because pH>pKa, the acid will mostly deprotonate. Since it deprotonates it will become the conjugate base, ChH3COO-. The conjugate base will have a net charge of -1.


so was this question asking the charge of the conjugate base?

Areli C 1L
Posts: 95
Joined: Wed Nov 14, 2018 12:19 am

Re: Midterm 3D

Postby Areli C 1L » Thu Feb 27, 2020 7:05 am

705121606 wrote:
Julie_Reyes1B wrote:Because pH>pKa, the acid will mostly deprotonate. Since it deprotonates it will become the conjugate base, ChH3COO-. The conjugate base will have a net charge of -1.


so was this question asking the charge of the conjugate base?


I believe so, well as the above question mentioned it asked for the net charge, but I couldn't comprehend it during the exam.


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