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Midterm 3D

Posted: Wed Feb 26, 2020 10:02 pm
by 705121606
For this question, it was asking what the net charge for acetic acid is when at ph 6 and pka 4.75. I was confused because I thought acids don't have charges. I wrote that the acid is neutral because when is dissociates wouldn't it become the conjugate base instead?

Re: Midterm 3D

Posted: Wed Feb 26, 2020 10:32 pm
by Amanda Lin 2I
Because the pH is higher than the pKa, CH3COOH will be deprotonated, forming CH3COO-, which has a charge of -1.

Re: Midterm 3D

Posted: Wed Feb 26, 2020 10:34 pm
by Julie_Reyes1B
Because pH>pKa, the acid will mostly deprotonate. Since it deprotonates it will become the conjugate base, ChH3COO-. The conjugate base will have a net charge of -1.

Re: Midterm 3D

Posted: Thu Feb 27, 2020 12:27 am
by 705121606
Julie_Reyes1B wrote:Because pH>pKa, the acid will mostly deprotonate. Since it deprotonates it will become the conjugate base, ChH3COO-. The conjugate base will have a net charge of -1.


so was this question asking the charge of the conjugate base?

Re: Midterm 3D

Posted: Thu Feb 27, 2020 7:05 am
by Areli C 1L
705121606 wrote:
Julie_Reyes1B wrote:Because pH>pKa, the acid will mostly deprotonate. Since it deprotonates it will become the conjugate base, ChH3COO-. The conjugate base will have a net charge of -1.


so was this question asking the charge of the conjugate base?


I believe so, well as the above question mentioned it asked for the net charge, but I couldn't comprehend it during the exam.