Textbook question 5.35 Part B

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ramiro_romero
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Joined: Sat Sep 07, 2019 12:16 am

Textbook question 5.35 Part B

Postby ramiro_romero » Mon Mar 09, 2020 12:12 am

For problem 5.35 in the textbook, how do we calculate the equilibrium constant from the given plot? I got the balanced rxn [2A -> B + 2C] If somebody could help for the equilibrium constant in part B I would really appreciate it

Brian Tangsombatvisit 1C
Posts: 119
Joined: Sat Aug 17, 2019 12:15 am

Re: Textbook question 5.35 Part B

Postby Brian Tangsombatvisit 1C » Mon Mar 09, 2020 2:56 pm

Once you figure out the chemical equation for the reaction, solving for the equilibrium constant is pretty straightforward. From the picture, you can see the equilibrium concentrations of the reactant and products based on where the number is when the line flattens out, because this means that the concentrations are at equilibrium. B and C are at 5 and 10, respectively, but A is a little harder to see. Using the equation, since B and C both start at 0, you can tell that the change in concentration (or x, if you were using an ICE table) is 5, so the decrease of A should be 2(5), or 10. Therefore, the final concentration of A is roughly 28-10, or 18. Plug these numbers into your equilibrium expression to get the equilibrium constant.

ramiro_romero
Posts: 90
Joined: Sat Sep 07, 2019 12:16 am

Re: Textbook question 5.35 Part B

Postby ramiro_romero » Mon Mar 09, 2020 6:31 pm

Thank you, I got the answer 1.54 but the textbook says 1.54 x 10^-2. I'm pretty sure it's a flaw in the solutions


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