Finding pOH of a solution given the pKb of a conjugate acid?

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WGaines_2E
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Joined: Mon Nov 18, 2019 12:18 am

Finding pOH of a solution given the pKb of a conjugate acid?

Postby WGaines_2E » Mon Mar 09, 2020 9:11 pm

"The pKb of the conjugate acid of chlorous acid is 12.08. A 0.15 M solution of chlorous acid was made to use as an inorganic acid in the synthesis of a new pharmaceutical. What is the pOH os this solution at equilibrium?

HClO2(aq) + H20(l) <> HClO-(aq) + H3O+(aq)

I wrote the ice table down correctly, got the correct pKa(1.92) and found that the pH was 6.45 also scored correct on the first exam. Why is pOH 14-6.45= 7.55?

chemboi
Posts: 101
Joined: Sat Jul 20, 2019 12:16 am

Re: Finding pOH of a solution given the pKb of a conjugate acid?

Postby chemboi » Mon Mar 09, 2020 9:34 pm

pOH + pH = 14

Jacob Motawakel
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Re: Finding pOH of a solution given the pKb of a conjugate acid?

Postby Jacob Motawakel » Tue Mar 10, 2020 1:07 am

Since you already found pH, you can use the equation pOH + pH = 14 to get 14 - pH = pOH and substitute your calculated pH.

Nawal Dandachi 1G
Posts: 102
Joined: Sat Sep 28, 2019 12:16 am

Re: Finding pOH of a solution given the pKb of a conjugate acid?

Postby Nawal Dandachi 1G » Tue Mar 10, 2020 1:11 am

you would just use pOH + pH = 14


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