Solving for the equilibrium constant

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205192823
Posts: 100
Joined: Wed Sep 18, 2019 12:19 am

Solving for the equilibrium constant

Postby 205192823 » Thu Mar 12, 2020 6:02 pm

Calculate the equilibrium constant from the following thermodynamic data for this reaction at 30 degrees Celsius.
CaCo3 (s) --> CaO (s) + CO2 (g), Delta S* = 181 J/mol and delta H* rxn= 221.5 kJ/ mol

I started this problem off by plugging in the values into delta G*= delta H*- Tdelta S*
and got 221.5 kJ/mol - (303K)(.181 kJ/mol) and got 166.657 kJ/mol but I didn't completely get the right answer and I was wanting to see what I did wrong. Did I use the wrong units?

MingdaH 3B
Posts: 133
Joined: Thu Jul 11, 2019 12:17 am

Re: Solving for the equilibrium constant

Postby MingdaH 3B » Thu Mar 12, 2020 6:27 pm

Your work looks right to me. Where is this problem from?

Ryan Yee 1J
Posts: 101
Joined: Sat Aug 17, 2019 12:16 am

Re: Solving for the equilibrium constant

Postby Ryan Yee 1J » Fri Mar 13, 2020 3:40 pm

Well, entropy is joules/(mol*K), but that shouldn't affect the answer that you got. The only thing that I could see possibly wrong is you added 273 instead of 273.15 for Kelvin conversion from celsius. But that shouldn't affect your answer too much.

Gurmukhi Bevli 4G
Posts: 49
Joined: Wed Nov 14, 2018 12:20 am

Re: Solving for the equilibrium constant

Postby Gurmukhi Bevli 4G » Wed Mar 18, 2020 1:09 am

^ Your work seems to be right.


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