Converting bar to mol/L
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Converting bar to mol/L
I've been having trouble with converting bars to mol/L. Does bar have to be converted to another unit first or can it just be immediately plugged into the ideal gas law equation?
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Re: Converting bar to mol/L
For the ideal gas equation, the pressure unit is atmospheres. So solve the ideal gas equation for pressure using the given temperature and concentration, and then convert the pressure value from atmospheres to bars. The conversion is about 0.99 atmospheres to 1 bar, so a direct one-to-one conversion from atmospheres to bars is a good conversion. Hope this helps!
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Re: Converting bar to mol/L
It can be immediately plugged into the ideal gas law equation. If you are trying to find mol/L make sure n/V is on one side of the equation so you solve for molarity. Also be sure to use the appropriate R value as the units of the R value are crucial for the correct answer. I believe you should use the R value of 0.08206 when using bar but correct me if I am wrong. I hope this helped!
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Re: Converting bar to mol/L
Here's the unit conversion:
is the units for the constant R.
In the lecture today, Dr. Lavelle said 1 bar is equal to approximately 1 atm, so we are usually given pressure in atm even though the SI unit is bar.
is the units for the constant R.
In the lecture today, Dr. Lavelle said 1 bar is equal to approximately 1 atm, so we are usually given pressure in atm even though the SI unit is bar.
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Re: Converting bar to mol/L
Hello! The ideal gas law uses atmospheres as the unit for pressure so you would usually want to convert the pressure to atm. Since 1 atm is equal to about 1.01 bar, however, it isn't really necessary to do any conversion calculations; you can just plug the pressure in bar into the ideal gas law. Hope this helps!
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Re: Converting bar to mol/L
Bar is a pressure unit, while mol/L is a concentration unit. So yes, some conversion will be required. As another commenter already showed (and as Dr. Lavella explained in today's lecture), you can convert partial pressure to concentration by rearranging the ideal gas law. This will leave you with:
n/V=P/RT
For this course, you can use the gas constant for atm, as 1 bar = 1 atm, so you can just plug your values into the equation above to convert bar/atm to a concentration.
n/V=P/RT
For this course, you can use the gas constant for atm, as 1 bar = 1 atm, so you can just plug your values into the equation above to convert bar/atm to a concentration.
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