HW problem

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emmaferry2D
Posts: 113
Joined: Wed Sep 30, 2020 9:47 pm

HW problem

Postby emmaferry2D » Thu Jan 07, 2021 11:47 am

how do you approach this problem
Use the information in Table 5G.2 to determine the value of K at 300 K for the reaction
2BrCl(g+H2(g)⇌Br2(g)+2HCl(g)
.

Andrew Wang 1C
Posts: 90
Joined: Wed Sep 30, 2020 10:11 pm
Been upvoted: 5 times

Re: HW problem

Postby Andrew Wang 1C » Thu Jan 07, 2021 11:57 am

Use table 5G.2 to find two reactions that, when added together, result in the desired reaction 2BrCl(g+H2(g)⇌Br2(g)+2HCl(g). Then you'd use the equilibrium constants for the two reactions that you found in the table to calculate K for the overall reaction by multiplying them together.

Hope this helps!

Yasmina Zaarour 1G
Posts: 90
Joined: Wed Sep 30, 2020 9:51 pm
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Re: HW problem

Postby Yasmina Zaarour 1G » Thu Jan 07, 2021 12:54 pm

To add onto the above response, the table might not give you the exact reactions that you need to add together; look for ones that just have the reactants and products that you need. Then, multiply the reactions through or reverse them to know how you need to change K. Remember that if you multiply a reaction by a factor, K becomes raised to that factor. If you have to reverse a reaction, K becomes the reciprocal of the original.

keely_bales_1f
Posts: 89
Joined: Wed Sep 30, 2020 9:41 pm

Re: HW problem

Postby keely_bales_1f » Thu Jan 07, 2021 6:07 pm

I would look at the responses written under the tab of Sapling Problem #5 (Of this section) because students have given very detailed and helpful answers there!

Andrew Yoon 3L
Posts: 87
Joined: Wed Sep 30, 2020 9:36 pm

Re: HW problem

Postby Andrew Yoon 3L » Thu Jan 07, 2021 10:16 pm

For this question, you would need to add two or more equations together. Adding equations together is the same as adding numbers except the substances on their sides, stay on their respective sides (so like on the left or on the right). Next, in order to get the equation to exactly match with all the coefficients, you want to multiply by a common factor. This effects the K value by raising it to that number that was multiplied the coefficients. If the reverse reaction was required, you raise the K value to -1. Once you have added the equations together and changed the K values to their appropriate value, multiply the new K values together. This will result a new K value that represents the reaction you were given.


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