Textbook Problem 5G.11

[Francesca_Borchardt_2D]

Hello,
I am a bit confused about the textbook problem 5G.11. Could someone explain how to solve this problem please?

Thank you!!

[Valerie Doan 3I]

Remember that solids and liquids are not included in the equilibrium constant or the reaction quotient. So, you would basically do the same calculation as K with products divided by reactants, each raised to their stoichiometric coefficients.
a) 1/[BCL3]^2
b) [H2S]^10 * [H3PO40^4
c) [BrF3]^2 / [F2]^3 * [Br]^2

[Bailey Giovanoli 1L]

So, the equation for Equilibrium constant, K, is the same as that of the reaction quotient, Q. However, I’m assuming you’re asking how to do it because there are no values given. In this case you would just express the equation symbolically. For example if your equation were 2O3-><-3O2, then you would have Q= [O2]^3/[O3]^2 because the production concentration goes on top and you raise the concentration to it stochiometric coefficient. Also, you could use partial pressure, the idea and outcome is the same.