Sapling Wk 1 Q2
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 105
- Joined: Wed Sep 30, 2020 9:49 pm
Sapling Wk 1 Q2
Hello, I've been having trouble trying to work this problem. I don't know if I'm doing it right but I multiplied the given equilibrium moles of O2 by 2 to get 0.240 mol for SO2. I then added the equilibrium moles of SO2 and O2 to get 0.360, which I then subtracted from the 0.820 initial moles of SO3 to get 0.46 mols of S03. I then converted each mol quantity to molarity using the 1.50 L and substituted it into the formula for the equilibrium constant of this reaction which is Kc = [SO2]^2[O2]/[S03]^2. If someone could help me that would be greatly appreciated. Thanks in advance!
-
- Posts: 112
- Joined: Wed Sep 30, 2020 10:03 pm
- Been upvoted: 3 times
Re: Sapling Wk 1 Q2
Allan Nguyen 2G wrote:Hello, I've been having trouble trying to work this problem. I don't know if I'm doing it right but I multiplied the given equilibrium moles of O2 by 2 to get 0.240 mol for SO2. I then added the equilibrium moles of SO2 and O2 to get 0.360, which I then subtracted from the 0.820 initial moles of SO3 to get 0.46 mols of S03. I then converted each mol quantity to molarity using the 1.50 L and substituted it into the formula for the equilibrium constant of this reaction which is Kc = [SO2]^2[O2]/[S03]^2. If someone could help me that would be greatly appreciated. Thanks in advance!
(repasting here just in case: https://imgur.com/a/cvDwPE6)
I know we got different numbers, but it's the same process. First, convert your SO3 and O2 moles into molar concentrations (divide their values by the volume), then you would create an ICE table, use the coefficients found in the equation for the change part, then calculate the equilibrium values by plugging in the numbers into a Kc equation.
Hope this helps!
-
- Posts: 89
- Joined: Wed Sep 30, 2020 10:00 pm
Re: Sapling Wk 1 Q2
A concentration table would be 0.304-x | +x| +1/2x|
Since 1/2x = 0.13, x = 0.26, so K = , which is 0.0.14. Hope this helps!
Since 1/2x = 0.13, x = 0.26, so K = , which is 0.0.14. Hope this helps!
-
- Posts: 112
- Joined: Wed Sep 30, 2020 10:01 pm
- Been upvoted: 1 time
Re: Sapling Wk 1 Q2
No this doesn't really help :/ for this question, how would you get to find X without knowing the Kc. I get how to do the rest of the problem, I am just stuck on the part where at the end of the ICE chart, we are trying to find what X is and I cant seem to figure out how
Return to “Equilibrium Constants & Calculating Concentrations”
Who is online
Users browsing this forum: No registered users and 10 guests