Sapling Wk 1 Q2

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Allan Nguyen 2G
Posts: 105
Joined: Wed Sep 30, 2020 9:49 pm

Sapling Wk 1 Q2

Postby Allan Nguyen 2G » Fri Jan 08, 2021 9:24 pm

Hello, I've been having trouble trying to work this problem. I don't know if I'm doing it right but I multiplied the given equilibrium moles of O2 by 2 to get 0.240 mol for SO2. I then added the equilibrium moles of SO2 and O2 to get 0.360, which I then subtracted from the 0.820 initial moles of SO3 to get 0.46 mols of S03. I then converted each mol quantity to molarity using the 1.50 L and substituted it into the formula for the equilibrium constant of this reaction which is Kc = [SO2]^2[O2]/[S03]^2. If someone could help me that would be greatly appreciated. Thanks in advance!
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Andre Fabian 1F
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Re: Sapling Wk 1 Q2

Postby Andre Fabian 1F » Fri Jan 08, 2021 10:19 pm

Allan Nguyen 2G wrote:Hello, I've been having trouble trying to work this problem. I don't know if I'm doing it right but I multiplied the given equilibrium moles of O2 by 2 to get 0.240 mol for SO2. I then added the equilibrium moles of SO2 and O2 to get 0.360, which I then subtracted from the 0.820 initial moles of SO3 to get 0.46 mols of S03. I then converted each mol quantity to molarity using the 1.50 L and substituted it into the formula for the equilibrium constant of this reaction which is Kc = [SO2]^2[O2]/[S03]^2. If someone could help me that would be greatly appreciated. Thanks in advance!


Image

(repasting here just in case: https://imgur.com/a/cvDwPE6)

I know we got different numbers, but it's the same process. First, convert your SO3 and O2 moles into molar concentrations (divide their values by the volume), then you would create an ICE table, use the coefficients found in the equation for the change part, then calculate the equilibrium values by plugging in the numbers into a Kc equation.


Hope this helps!

Anthony_3C
Posts: 89
Joined: Wed Sep 30, 2020 10:00 pm

Re: Sapling Wk 1 Q2

Postby Anthony_3C » Sat Jan 09, 2021 6:43 am

A concentration table would be 0.304-x | +x| +1/2x|
Since 1/2x = 0.13, x = 0.26, so K = , which is 0.0.14. Hope this helps!

Sophia Kalanski 1A
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Re: Sapling Wk 1 Q2

Postby Sophia Kalanski 1A » Sat Jan 09, 2021 4:24 pm

No this doesn't really help :/ for this question, how would you get to find X without knowing the Kc. I get how to do the rest of the problem, I am just stuck on the part where at the end of the ICE chart, we are trying to find what X is and I cant seem to figure out how


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