Lecture Question

[Emily_Stenzler_2H]

In lecture today (1/13) what did Dr. lavelle mean when he said CH3COOH was acting as a base (22:36)? I thought anything with -COOH was a weak acid.

[Laura 3l]

I was honestly confused by that too because he then goes on by saying that the equilibrium constant for this reaction is Ka because we have a weak acid in our reaction.

[Colin Juett 2F]

I'm pretty sure he misspoke. That compound is a weak acid.

[Sheryl Ocampo 1D]

He said later on that it was a weak acid so I think it was just a mistake

[Andy Hon 3E]

Rewatched the lecture and can confirm that Dr. Labelle accidentally misspoke.

[Vanessa Perez]

I was also confused on this, but it is a weak acid

[Joseph Hsing 2C]

CH3COOH should be an acid.

[Mary Shih 3J]

CH3COOH is ab acid I think he just made a mistake

[Rahul Sobti 1E]

CH3COOH is an acid and CH3COO- is its conjugate base.

[Chem_Mod]

Oops! I did misspeak.

Right next to CH₃COOH(aq) is written WEAK ACID.

Definitely a weak acid. :-)

Most unusual for me. I need to rest up a bit this weekend. :-)