Sapling #3

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Molly Posta 1H
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Joined: Wed Sep 30, 2020 10:05 pm
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Sapling #3

Postby Molly Posta 1H » Fri Jan 15, 2021 3:46 pm

I'm having trouble with question 3 on the first Sapling assignment. I attached a picture of my work. I think I set up the ICE table correctly, but I'm not sure because the equation it gives me seems different from what it usually looks like for these types of problems. If it is correct, how do I go about solving for x?

Mikayla Kwok 3K
Posts: 99
Joined: Wed Sep 30, 2020 9:51 pm

Re: Sapling #3

Postby Mikayla Kwok 3K » Fri Jan 15, 2021 3:49 pm

Your last equation should read 53.3 = 4x^2/(0.3-x)(0.3-x). This is because you are squaring (2x), not just the (x) in the equilibrium expression.

Posts: 87
Joined: Fri Aug 30, 2019 12:17 am

Re: Sapling #3

Postby LReedy_3C » Fri Jan 15, 2021 3:54 pm

Once you make that change, you go about solving for x like we did in class using the quadratic formula

Andrew Yoon 3L
Posts: 87
Joined: Wed Sep 30, 2020 9:36 pm

Re: Sapling #3

Postby Andrew Yoon 3L » Fri Jan 15, 2021 8:51 pm

When your squaring your products, make sure you are squaring both the variable and the coefficient. (2x)^2 should equal 4x^2. Next, you should multiply out the denominator. Then, you should solve for x using the quadratic formula.

Jiapeng Han 1C
Posts: 85
Joined: Wed Sep 30, 2020 9:50 pm

Re: Sapling #3

Postby Jiapeng Han 1C » Fri Jan 15, 2021 11:15 pm

This is actually a very classical mistake when doing the ICE table! It should be (2x)^2, that is 4x^2, instead of 2x^2!

Navdha Sharma 3J
Posts: 96
Joined: Wed Sep 30, 2020 9:46 pm

Re: Sapling #3

Postby Navdha Sharma 3J » Sat Jan 16, 2021 9:56 am

I did the same mistake! The numerator should be 4x^2 and not 2x^2

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