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### textbook question 5.35

Posted: Mon Jan 18, 2021 11:44 am
In this question where do we get the values for Pa,Pb, and Pc
The textbook answer says they are (18/100),(5/100),&(10/100)

### Re: textbook question 5.35

Posted: Mon Jan 18, 2021 12:24 pm
Which section is this question from? I can't find it.

### Re: textbook question 5.35

Posted: Mon Jan 18, 2021 12:43 pm
First, look at where the curves flatten as this indicates that the reaction has reached equilibrium, and therefore will allow us to find the equilibrium Pa, Pb, and Pc values. Also, notice that the y axis is labeled in units of kPa. The equilibrium pressure for A is approximately 18 kPa, the equilibrium pressure for B is approximately 5 kPa, and the equilibrium pressure for C is approximately 10 kPa. When we calculate the equilibrium constant, we need to use units of atm or bars, so we need to convert the pressures that we found in kPa to pressure in bars. If you look at the constants and equations sheet on Dr. Lavelle's website, you'll see that there are 100 kPa in 1 bar. Therefore, the equilibrium pressure for A is 18/100 bar, the equilibrium pressure for B is approximately 5/100 bar, and the equilibrium pressure for C is 10/100 bar. You can now plug these values into the expression for the equilibrium constant to calculate a value for the equilibrium constant. I hope this helps!