Ka and Kb Formula
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Ka and Kb Formula
So when you're given Ka it says the formula is [H+][A-]/[HA]. In the video I watched it said you can simply write it as just x^2/[molarity - x] since [H+] and [A-] are equal. Is this statement always true?
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Re: Ka and Kb Formula
I'm not completely sure, so it'd be great if someone could fact check me!:
We've mostly been working with monoprotic acids, so this holds true for most of the problems we've done. However, note that it depends on the chemical equation's coefficients. If, for example, two moles of A- are gained from each mole of HA lost, then A- would have -2x, which would make [H+] and [A-] different. If it's monoprotic like the problems we've been doing so far, you don't have to worry about this!
We've mostly been working with monoprotic acids, so this holds true for most of the problems we've done. However, note that it depends on the chemical equation's coefficients. If, for example, two moles of A- are gained from each mole of HA lost, then A- would have -2x, which would make [H+] and [A-] different. If it's monoprotic like the problems we've been doing so far, you don't have to worry about this!
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Re: Ka and Kb Formula
I think this is honestly true, but I would just always write [H+][A-], so then it sticks that you're multiplying the conjugate base and prevent any problems
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Re: Ka and Kb Formula
What key words should we look for in order to determine if we should be using Ka and Kb? This concept caused me a few issues with the homework
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Re: Ka and Kb Formula
Kandyce Lance 3E wrote:What key words should we look for in order to determine if we should be using Ka and Kb? This concept caused me a few issues with the homework
In the homework, you'd need to use Ka when solving for a weak acid, and Kb when solving for weak bases. You solve for one by dividing 1x10^-14 by the other. The processes for using them are similar.
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Re: Ka and Kb Formula
Yeah I think this is true for monoprotic acids, which is mostly what we work with in class!
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Re: Ka and Kb Formula
This statement is ALWAYS true of weak monoprotic acids / bases but you can make assumptions about the x value on the bottom of the expression if the KA is 10^-3 or less, such that x on the bottom roughly = 0, but x on the top STILL = x.
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