textbook 5.35

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Talia Leano 2H
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Joined: Wed Sep 30, 2020 10:10 pm

textbook 5.35

Postby Talia Leano 2H » Thu Jan 28, 2021 12:25 am

How do you determine this is 2A -> 2B + C ?
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Ritika Prasad 1A
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Re: textbook 5.35

Postby Ritika Prasad 1A » Thu Jan 28, 2021 12:56 am

I believe the solution manual states that the answer to part a would be: 2A --> B + 2C.

According to the graph, looking at the changes in pressure from initial state to equilibrium, ΔA = 10, ΔB=5, and ΔC=10.

From this, the ratio of change in A:B:C would be 2:1:2. This ratio then provides the coefficients for the reactants and products in the equation and since this is decomposition of A into B and C, the equation would be 2A --> B + 2C.

Adrienne Yuh 2B
Posts: 110
Joined: Wed Sep 30, 2020 10:03 pm

Re: textbook 5.35

Postby Adrienne Yuh 2B » Thu Jan 28, 2021 3:06 am

I was also wondering this, but the relative ratios of change (delta) creates the 2:1:2 pattern.

allyssa bradley 1H
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Joined: Wed Sep 30, 2020 9:47 pm

Re: textbook 5.35

Postby allyssa bradley 1H » Sun Mar 07, 2021 12:50 pm

Ritika Prasad 1A wrote:I believe the solution manual states that the answer to part a would be: 2A --> B + 2C.

According to the graph, looking at the changes in pressure from initial state to equilibrium, ΔA = 10, ΔB=5, and ΔC=10.

From this, the ratio of change in A:B:C would be 2:1:2. This ratio then provides the coefficients for the reactants and products in the equation and since this is decomposition of A into B and C, the equation would be 2A --> B + 2C.


Hey Ritika, this description was super helpful to me! I was just focused on those end values, which clearly are pretty weird. Sorry for dredging up your post from over a month ago and it's ok if you can't answer this question, but do we use the end values the reaction plateaus on for our K value? Even with the new coefficients, my K value doesn't quite match what the book has, so I feel like I'm still messing something up.

Ritika Prasad 1A
Posts: 50
Joined: Mon Jan 04, 2021 11:26 am

Re: textbook 5.35

Postby Ritika Prasad 1A » Wed Mar 10, 2021 6:57 pm

allyssa bradley 1H wrote:
Hey Ritika, this description was super helpful to me! I was just focused on those end values, which clearly are pretty weird. Sorry for dredging up your post from over a month ago and it's ok if you can't answer this question, but do we use the end values the reaction plateaus on for our K value? Even with the new coefficients, my K value doesn't quite match what the book has, so I feel like I'm still messing something up.


Hey Allyssa! I'm glad that explanation helped! For the K value, yes, I believe you would use the end values because those are the values at equilibrium, so K = [(Partial Pressure of B)*(Partial Pressure of C)^2]/[(Partial Pressure of B)^2] so in simplified form: K = [(B)(C^2)]/[(A^2)].

Since we're not given exact values at the end, we can estimate from the graph that the partial pressure of A is 18, C is 10, and B is 5.

In the solution manual, I believe the values are divided by 100 because the y-axis scale is P/kPa, and standard atmospheric pressure (or 1 atm) is defined as 101.325 kPa.

So then finally, you get [(5/100)*(10/100)^2]/[(18/100)^2] = 1.54 x 10^-2, which matches the solution in the manual! I hope that helps :)


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