Partial Pressure Calculation?

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Antonio Melgoza 2K
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Joined: Fri Sep 25, 2015 3:00 am

Partial Pressure Calculation?

Postby Antonio Melgoza 2K » Wed Nov 11, 2015 5:43 pm

The answer for the attached HW problem is 5.4 bar, but I dont understand why. Why is the equation (25)(1.18)/(5.43) instead of (25)(5.43)/(1.18)?
HW prob 27.png
HW prob 27.png (12.12 KiB) Viewed 316 times

Posts: 20
Joined: Fri Sep 25, 2015 3:00 am

Re: Partial Pressure Calculation?

Postby 704564167 » Wed Nov 11, 2015 9:47 pm

The equation is like that because K= (PPCl3)(PCl2)/(PPCl5)

and so when you're solving for the partial pressure of PPCl3 you can rearrange the equation to be this:

PPCl3= (K)(PPCl5)/(PCl2)

After plugging in the values you will get PPCl3=(25)(1.18)/(5.43)

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