Ka vs Kb

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Isabelle Hales 1J
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Ka vs Kb

Postby Isabelle Hales 1J » Sat Mar 13, 2021 11:56 pm

Going off of Dr. Lavelle's example in the review lecture this week, how do you determine whether the reaction you are observing has a Ka or Kb value?

Alex Mele 2A
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Re: Ka vs Kb

Postby Alex Mele 2A » Sat Mar 13, 2021 11:57 pm

Ka is for acid dissociation, and Kb is for base dissociation.

Geethika Janga 1L
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Re: Ka vs Kb

Postby Geethika Janga 1L » Sat Mar 13, 2021 11:58 pm

Ka is the value used during acid dissociation reactions and Kb is used for bases.

Christine Ma 3L
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Re: Ka vs Kb

Postby Christine Ma 3L » Sun Mar 14, 2021 12:03 am

You can just look at the species that is disassociating! If the species that is disassociating is an acid like in the example (ie. produces hydronium ions), then it has a Ka value (which can be calculated using its conjugate base's Kb value). Likewise, if the species that is disassociating is a base (ie. produces hydroxide ions), then it has a Kb value (that can be calculated using its conjugate acid's Ka value). Hope this helps!

Taylor K 2D
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Re: Ka vs Kb

Postby Taylor K 2D » Sun Mar 14, 2021 12:05 am

Usually Ka is associated with acids and Kb with bases. If you need to convert between the two, just use the equation Ka x Kb = Kw = 1x10^-14

Manseej Khatri 2B
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Re: Ka vs Kb

Postby Manseej Khatri 2B » Sun Mar 14, 2021 12:20 am

Adding on, I believe if the equilibrium expression written has [H3O+] or [H+] in the numerator, its a ka expression since its generating H+ in solution, and if it has an [OH-] its a kb expression since its generating OH- in solution.


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