The Ka of a monoprotic weak acid is 0.00340. What is the percent ionization of a 0.109 M solution of this acid?
I used Ka = x^2/(.109-x) and solved the quadratic x^2 + .0034x - .003706 to get x=0.0592 and used 0.0592/.109 x 100% to get a percent ionization of 54.3%, however that's incorrect? Does anyone know where I went wrong?
Achieve Week 3 #2
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Devika Nair 2D
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Re: Achieve Week 3 #2
Your c value is -0.003706, but 0.00340(-0.109) is -0.0003706! Just missing a zero.
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