achieve week 1, #5

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Vicky Tong 3E
Posts: 104
Joined: Fri Sep 24, 2021 5:30 am

achieve week 1, #5

Postby Vicky Tong 3E » Sun Jan 16, 2022 1:49 am

When completing this question: I choose the equations: Ka and Kc to get the given equation.

So I calculated Ka: 160^3 by multiplying 3 to the equation, and Kc=(1/(3.6x10^-2)) by inversing the equation.

When I added them together: 106^3 + (1/(3.6x10^-2)) = 4.096 x 10^6. I'm not sure what I did wrong because this is incorrect.

Help would be appreciated!
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Devyn Chun 3I
Posts: 101
Joined: Fri Sep 24, 2021 7:14 am

Re: achieve week 1, #5

Postby Devyn Chun 3I » Sun Jan 16, 2022 3:01 am

You did it correctly, except instead of adding 160^3 and (1/(3.6x10^-2)), you need to multiply them together. If try to create the exact fraction combination for Kp from the equations provided, you need to multiply the created fractions to cancel each other out/make the equation equal to the original.

( [HI]^2 / [H2][I2] )^3 * ( [N2][H2]^3 / [NH3]^2 )

You can see that the H2 values will cancel out when you multiply them creating the original fraction from the original Kp. Basically, when you are creating a chemical equation from many other chemical equations you need to multiply Kp instead of add. Hopefully this helped!


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