6B #11a(ii) Textbook Prob
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6B #11a(ii) Textbook Prob
Hi! I have found the molar concentration of hydroxide ions in the diluted solution but am unsure how to determine it for the original solution. I did 0.18 M*(0.5 L/0.005 L) but the book did 0.18 M*(0.005 L/0.5 L). Can you explain this difference? Thanks!
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Re: 6B #11a(ii) Textbook Prob
I think you're correct. It should be 0.18M*(0.5L/0.005L) and that's what the Atkin's Solutions Manual says. In the M1V1 = M2V2 equation, the known molarity and volume of one solution stays together on one side of the division line. If I designate diluted solution as #2 and original solution is #1, we must solve for M1. M1 = (M2V2)/V1, so to get the answer, it should be M1 = (0.18 M * 0.5 L)/(0.005 L).
Re: 6B #11a(ii) Textbook Prob
The method that you used was correct because you correctly identified the equation M1V1 = M2V2 and you used the right values to describe the initial and final volumes and molar concentrations. I also used 0.18*0.5/0.005 and I got 18M OH-.
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