Textbook 5I.13 part a

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405745446
Posts: 100
Joined: Fri Sep 24, 2021 5:37 am

Textbook 5I.13 part a

Postby 405745446 » Thu Jan 27, 2022 1:21 pm

Hello,
I'm unsure about where my reasoning/ work went wrong for this problem:
I converted 2.0mmolCl2(g) into moles by dividing by 1000 and then dividing by 2L to get it into Molarity. I set up my ice table like this:

cl2 2Cl
0.001M 0
-x +2x
0.001-x 2x

Then from information from table 5g.2, I found that the K value for cl2 heated to 1000k is 1.0x10^-5
So my equation looks like

x^2/ 0.001 = 1.0x10^-5

and after found x to be 1x10^-4
which gives me the answer of 2(1x10^-4) = 2x10^-4 which is not the answer.

Any help is appreciated and thank you in advance

Anthony Tam
Posts: 100
Joined: Fri Sep 24, 2021 7:04 am

Re: Textbook 5I.13 part a

Postby Anthony Tam » Thu Jan 27, 2022 2:11 pm

For me, I used the Kc value of 1.2x10^-7. Try that value and see if that works for you.

Aaron Li 1D
Posts: 100
Joined: Fri Sep 24, 2021 5:12 am
Been upvoted: 1 time

Re: Textbook 5I.13 part a

Postby Aaron Li 1D » Thu Jan 27, 2022 7:46 pm

Like the person above, use that K value. Also remember to make it 2x squared instead of just x squared in the K equation since you used 2x in the ice table.


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