Textbook 5I.23

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Ashley Hiti 1K
Posts: 139
Joined: Fri Sep 24, 2021 5:10 am

Textbook 5I.23

Postby Ashley Hiti 1K » Fri Jan 28, 2022 7:10 pm

I am not sure if I am just doing the math wrong or plugging it in to my calculator wrong but when I calculate it, (0.0478)(0.0478)/((0.152)(0.157)^3) does not come out to 3.88

I solved the problem the same way as the solutions and got the same equilibrium concentration values but I cannot make that equal the Kc solution = 3.88

Is there a step I am missing or is anyone else having this problem?

Jose Angelo Grajeda 2D
Posts: 100
Joined: Fri Sep 24, 2021 6:26 am

Re: Textbook 5I.23

Postby Jose Angelo Grajeda 2D » Fri Jan 28, 2022 7:42 pm

I believe that is correct! If you compute using the correct sig figs (rounding 0.1566 to 0.157, for example), and use parentheses in the calculator, it comes out to about 3.88. When I originally did this problem, I did not round to the sig figs before computing and got 3.909. However, plugging it in exactly how it is written there should work I believe (the fraction bar in a TI-84 could help too).


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